A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done?(1 point)

Responses

0 J
0 J

24,600 J
24,600 J

705 J
705 J

18.2 J

1 answer

To calculate the work done by the car, we can use the formula:

\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]

where:

  • Work is in joules (J),
  • Force is in newtons (N),
  • Distance is in meters (m),
  • \(\theta\) is the angle between the force and the direction of motion.

Assuming the force is applied in the direction of the movement (which means θ = 0 degrees, and cos(0) = 1), the equation simplifies to:

\[ \text{Work} = \text{Force} \times \text{Distance} \]

Plugging in the values:

\[ \text{Force} = 36.8 , \text{N} \] \[ \text{Distance} = 668 , \text{m} \]

Now, calculate the work done:

\[ \text{Work} = 36.8 , \text{N} \times 668 , \text{m} = 24,605.4 , \text{J} \]

Rounding to the nearest whole number gives approximately 24,600 J.

Therefore, the correct response is:

24,600 J