d1 = 2t^2 + 2t
d2 = 20t
the time of overtaking is when d1 = d2
2t^2 + 2t = 20t
t^2 - 9t = 0
t(t - 9) = 0
interpret this equation, and find the answer to your question from it.
A car and a truck starts from same point along same direction ,car with initial speed 2m/s and acceleration 2 m/s^2 and truck with a constant speed 20 m/s ,find the time after which car will overtake the truck
2 answers
d = vt + 1/2 at^2
so d1 = 2t + 1t^2
so d1 = 2t + 1t^2