vi = 0 m/s
a = 3.9 m/s^2
d = 56m
vf^2 = vi^2 +2a*d
vf^2 = 0 + 2(3.9*56)
vf^2 = 436.8 m/s
vf = 20.8997 m/s
=21 m/s
This is the speed of the car after it has traveled 56m.
A car accelerates uniformly in a straight line
from rest at the rate of 3.9 m/s2
.
What is the speed of the car after it has
traveled 56 m?
Answer in units of m/s.
1 answer