A) k.E = 1/2MV^2= 1/2*800*441=176400
NOW , POWER = 176400/6.1 = 2.94E2Watt
SIMILARLY SOLVE THE NEXT PART PUTTING THE GIVEN MASS
A car accelerates uniformly from rest to 21.0 m/s in 6.1 s along a level stretch of road. Ignoring friction, determine the average power required to accelerate the car if the weight of the car is the following.
A) 8.0e3N B) 1.2e4N
(The answer needs to be in Watts)
1 answer