a captive balloon is connected to a ground station A by a cable of length 842 ft inclined 65 degrees to the horizontal. In a vertical plane with the balloon and its station and on the opposite side of the balloon from A, a target B was sighted from the balloon on a level with A. if the angle of depression ofthe target from the balloon is 4 degrees, find the distance from the target to a point C directly under the balloon.

Answer 1

The cable is the hyp. of a rt. triangle,
and the ht. of the balloon is the ver.
side.

h = 842*sin65 = 763.1 Ft. = Ht. of the balloon.

Tan4 = h/BC
BC = h/Tan4 = 763.1/Tan4 = 10,913 Ft =
Distance from the target to point C.