I'm stuck, please help
the second question the above question is Find the capacitance of the parallel plates.
A capacitor is constructed with two parallel metal plates each with an area of 0.61 m^2 and separated by d = 0.80 cm. The two plates are connected to a 5.0-volt battery. The current continues until a charge of magnitude Q accumulates on each of the oppositely charged plates. Find the charge Q.
3 answers
I have to use this formula to find Q Q = CΔV, and C = (ε0*A)/d
These are what I did but don't know what ε0 is
C= (ε0*0.61 m^2 )/.0080m= stuck here. Is there anybody know what to do from here?
These are what I did but don't know what ε0 is
C= (ε0*0.61 m^2 )/.0080m= stuck here. Is there anybody know what to do from here?
ε0=8.85*10^-12
C=[(8.85*10^-12)*.61]/.008=
Q=([(8.85*10^-12)*.61]/.008=)*5=
Parallel Plate Capacitor Capacitance Calculator for second question
www.daycounter.com/Calculators/Plate-Capacitor-Calculator.phtml
C=[(8.85*10^-12)*.61]/.008=
Q=([(8.85*10^-12)*.61]/.008=)*5=
Parallel Plate Capacitor Capacitance Calculator for second question
www.daycounter.com/Calculators/Plate-Capacitor-Calculator.phtml
2 answers