A cannon of mass 200kg, fires a cannonball with a mass of 10kg. The cannon ball leaves the barrel of the cannon with a velocity of 60 m/s. Using the law of conservation of momentum , explain what happens to the cannon when the cannon ball is fired. (Answer should include calculation.)

Answer 1

Well, I guess this cannon is fired horizontally.

final momentum = 200 v + 10 *60 = initial momentum = 0
so
v = - 600/200 = -3 m/s

Answer 2

Why is it 200v ??Is the formula used :
m1v2+m2v2=(m1+m2)v ???

Confusedd

Answer 3

Pbefore = Pafter
(m1v2)+(m2v2) = (m1v2)+(m2v2)