Vo = 210m/s[70o]
Xo = 210*cos70 = 71.82 m/s.
Yo = 210*sin70 = 197.3 m/s.
1. h = (Y^2-Yo^2)/2g=(0-197.3^2)/-19.6 =
1986 m.
A cannon launches a ball with the initial speed of 210 m/s at a 70 degree angle.
1. How high will the cannonball go?
2. If the cannonball has a mass of 25kg how much work does it take to launch the cannonball to that height?
1 answer