A cannon is fired from a cliff 200 m high downward at an angle of 30o with respect to the horizontal. If the muzzle velocity is 34 m/s, what is its speed (in m/s) when it hits the ground?

Answer 1

Ignoring air-resistance, equate energies:

(PE+KE)initial = (PE+KE)final

mgh+(1/2)mu² = (1/2)mv²
Solve for v.

I get approx. 71 m/s.

Answer 2

thank you so much!

Answer 3

You're welcome!