a cannon fires a shell with a speed of 84m/s.when the cannon is inclined at 45 degree,the horizontal distance covered is observed as 630 m.what is the percentage decrease in the horizontal distance observed due to air resistance?

Answer 1

Vo = 84m/s[45o].

Dx = Vo^2*sin(2A)/g=84^2*sin90/9.8=720 m
with zero wind.

(720-630)/720 * 100% = 12.5% Decrease.