A cannon fires a shell straight upward; 2.4 s after it is launched, the shell is moving upward with a speed of 18 m/s. Assuming air resistance is negligible, find the speed (magnitude of velocity) of the shell at launch and 5.4 s after the launch.

Question

What is the velocity at launch?

Velocity after 5.4s?

Answer 1

vf=vi-gt
18=vi-9.8(2.4) solve for vi

using that vi, solve at time 5.4sec