To find the volume of a cylinder (which is the shape of a can), you can use the formula:
\[ V = \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height, and
- \( \pi \) is approximately 3.14.
Given:
- Height \( h = 6 \) inches,
- Radius \( r = 3 \) inches,
- \( \pi \approx 3.14 \).
Now, plug in the values:
\[ V = 3.14 \times (3)^2 \times 6 \]
First, calculate \( (3)^2 \):
\[ (3)^2 = 9 \]
Now, substitute back in:
\[ V = 3.14 \times 9 \times 6 \]
Calculate \( 9 \times 6 \):
\[ 9 \times 6 = 54 \]
Now, multiply:
\[ V = 3.14 \times 54 \]
Calculating \( 3.14 \times 54 \):
\[ 3.14 \times 54 = 169.56 \]
Thus, the volume of the can is:
\[ \boxed{169.56} \text{ cubic inches} \]