To find the surface area of the can, we need to find the area of the curved part and the area of the top and bottom.
The curved part of the can is a cylinder, and the formula for the lateral surface area of a cylinder is given by $2\pi rh$, where $\pi \approx 3.14$, $r$ is the radius, and $h$ is the height. Since the diameter is 2.5 inches, the radius is $2.5/2 = 1.25$ inches. Thus, the area of the curved part is $2 \cdot 3.14 \cdot 1.25 \cdot 3.5 \approx 21.91$ square inches.
The top and bottom of the can are each circles, and the formula for the area of a circle is given by $\pi r^2$. Thus, each circle has an area of $3.14 \cdot (1.25)^2 \approx 4.91$. Since there are two circles, the total area of the top and bottom is $2 \cdot 4.91 = 9.82$ square inches.
Therefore, the total surface area of the can is $21.91 + 9.82 = 31.73$. Rounded to the nearest inch, the label will need $\boxed{32}$ square inches of paper.
A can of carrots has a diameter of 2.5 inches and a height of 3.5 inches. How many square inches of paper will be needed for the label on the outside of the can.Use 3.14 for pi and round your answer to the nearest inch.
7 answers
wrong
I apologize for the incorrect response. Let's recalculate the surface area of the can to determine the correct amount of paper needed for the label.
The curved part of the can is a cylinder, and the formula for the lateral surface area of a cylinder is given by $2 \pi r h$, where $r$ is the radius and $h$ is the height. Given that the diameter is 2.5 inches, the radius is $2.5/2 = 1.25$ inches. The height of the can is 3.5 inches.
Therefore, the area of the curved part is $2\pi \cdot 1.25 \cdot 3.5 = 8.75\pi \approx 27.53$ square inches.
The top and bottom of the can are each circles with a radius of 1.25 inches. The formula for the area of a circle is given by $\pi r^2$. Thus, each circle has an area of $\pi \cdot (1.25)^2 = 4.91$ square inches. Since there are two circles, the total area of the top and bottom is $2 \cdot 4.91 = 9.82$ square inches.
Therefore, the total surface area of the can is $27.53 + 9.82 = 37.35$ square inches. Rounded to the nearest inch, the label will require $\boxed{37}$ square inches of paper.
The curved part of the can is a cylinder, and the formula for the lateral surface area of a cylinder is given by $2 \pi r h$, where $r$ is the radius and $h$ is the height. Given that the diameter is 2.5 inches, the radius is $2.5/2 = 1.25$ inches. The height of the can is 3.5 inches.
Therefore, the area of the curved part is $2\pi \cdot 1.25 \cdot 3.5 = 8.75\pi \approx 27.53$ square inches.
The top and bottom of the can are each circles with a radius of 1.25 inches. The formula for the area of a circle is given by $\pi r^2$. Thus, each circle has an area of $\pi \cdot (1.25)^2 = 4.91$ square inches. Since there are two circles, the total area of the top and bottom is $2 \cdot 4.91 = 9.82$ square inches.
Therefore, the total surface area of the can is $27.53 + 9.82 = 37.35$ square inches. Rounded to the nearest inch, the label will require $\boxed{37}$ square inches of paper.
35 in, 67 in, 24 in, or 27 in
To find the surface area of the can, we need to find the area of the curved part and the area of the top and bottom.
The curved part of the can is a cylinder, and the formula for the lateral surface area of a cylinder is given by $2\pi rh$, where $r$ is the radius and $h$ is the height. Given that the diameter is 2.5 inches, the radius is $2.5/2 = 1.25$ inches. The height of the can is 3.5 inches.
Therefore, the area of the curved part is $2\pi \cdot 1.25 \cdot 3.5 = 8.75\pi \approx 27.53$ square inches.
The top and bottom of the can are each circles with a radius of 1.25 inches. The formula for the area of a circle is given by $\pi r^2$. Thus, each circle has an area of $\pi \cdot (1.25)^2 = 4.91$ square inches. Since there are two circles, the total area of the top and bottom is $2 \cdot 4.91 = 9.82$ square inches.
Therefore, the total surface area of the can is $27.53 + 9.82 = 37.35$ square inches. Rounded to the nearest inch, the label will require $\boxed{37}$ square inches of paper.
The curved part of the can is a cylinder, and the formula for the lateral surface area of a cylinder is given by $2\pi rh$, where $r$ is the radius and $h$ is the height. Given that the diameter is 2.5 inches, the radius is $2.5/2 = 1.25$ inches. The height of the can is 3.5 inches.
Therefore, the area of the curved part is $2\pi \cdot 1.25 \cdot 3.5 = 8.75\pi \approx 27.53$ square inches.
The top and bottom of the can are each circles with a radius of 1.25 inches. The formula for the area of a circle is given by $\pi r^2$. Thus, each circle has an area of $\pi \cdot (1.25)^2 = 4.91$ square inches. Since there are two circles, the total area of the top and bottom is $2 \cdot 4.91 = 9.82$ square inches.
Therefore, the total surface area of the can is $27.53 + 9.82 = 37.35$ square inches. Rounded to the nearest inch, the label will require $\boxed{37}$ square inches of paper.
its not 37 the options are 35 in. squared, 67 in squared, 24 in squared or 27 in squared
Apologies for the confusion. Let's calculate the surface area of the can using the correct formulas and round the answer to the nearest inch.
The curved part of the can is a cylinder, and the formula for the lateral surface area of a cylinder is given by $2\pi rh$, where $r$ is the radius and $h$ is the height. Given that the diameter is 2.5 inches, the radius is $2.5/2 = 1.25$ inches. The height of the can is 3.5 inches.
Therefore, the area of the curved part is $2\pi \cdot 1.25 \cdot 3.5 = 8.75\pi \approx 27.53$ square inches.
The top and bottom of the can are each circles with a radius of 1.25 inches. The formula for the area of a circle is given by $\pi r^2$. Thus, each circle has an area of $\pi \cdot (1.25)^2 = 4.91$ square inches. Since there are two circles, the total area of the top and bottom is $2 \cdot 4.91 = 9.82$ square inches.
Therefore, the total surface area of the can is $27.53 + 9.82 = 37.35$ square inches. Rounded to the nearest inch, the label will require $\boxed{37}$ square inches of paper.
I apologize for the previous incorrect response.
The curved part of the can is a cylinder, and the formula for the lateral surface area of a cylinder is given by $2\pi rh$, where $r$ is the radius and $h$ is the height. Given that the diameter is 2.5 inches, the radius is $2.5/2 = 1.25$ inches. The height of the can is 3.5 inches.
Therefore, the area of the curved part is $2\pi \cdot 1.25 \cdot 3.5 = 8.75\pi \approx 27.53$ square inches.
The top and bottom of the can are each circles with a radius of 1.25 inches. The formula for the area of a circle is given by $\pi r^2$. Thus, each circle has an area of $\pi \cdot (1.25)^2 = 4.91$ square inches. Since there are two circles, the total area of the top and bottom is $2 \cdot 4.91 = 9.82$ square inches.
Therefore, the total surface area of the can is $27.53 + 9.82 = 37.35$ square inches. Rounded to the nearest inch, the label will require $\boxed{37}$ square inches of paper.
I apologize for the previous incorrect response.
1 answer