A can is in the shape of a cylinder. The can has a volume of 450 cubic inches and a diameter of 4 inches. To the nearest tenth of an inch, what is the height of the can?

Answer 1

First, we need to find the height of the cylinder using the formula for the volume of a cylinder:

V = πr^2h

Given that the diameter of the cylinder is 4 inches, the radius (r) is half of the diameter, so r = 2 inches.

Plugging in the values we have:

450 = π(2)^2h
450 = 4πh
h = 450 / (4π)
h ≈ 35.8 inches

Therefore, the height of the can is approximately 35.8 inches.