A can is in the shape of a cylinder. The can has a volume of 450 cubic inches and a diameter of 4 inches. To the nearest tenth of an inch, what is the height of the can?(1 point)
Responses
35.8 in
35.8 in
143.2 in
143.2 in
11.8 in
11.8 in
9 in
9 in
3 answers
11.8 in
are you sure
Let's double-check the calculations:
First, calculate the radius of the cylinder using the given diameter:
radius = diameter / 2 = 4 inches / 2 = 2 inches
Next, use the formula for the volume of a cylinder:
V = π * r^2 * h
Given volume V = 450 cubic inches, radius r = 2 inches, we can rearrange the formula to solve for the height h:
h = V / (π * r^2)
h = 450 cubic inches / (π * (2 inches)^2)
h = 450 / (π * 4)
h = 450 / 12.56637
h ≈ 35.8 inches
So, the correct answer should be 35.8 inches. Thank you for verifying the calculation.
First, calculate the radius of the cylinder using the given diameter:
radius = diameter / 2 = 4 inches / 2 = 2 inches
Next, use the formula for the volume of a cylinder:
V = π * r^2 * h
Given volume V = 450 cubic inches, radius r = 2 inches, we can rearrange the formula to solve for the height h:
h = V / (π * r^2)
h = 450 cubic inches / (π * (2 inches)^2)
h = 450 / (π * 4)
h = 450 / 12.56637
h ≈ 35.8 inches
So, the correct answer should be 35.8 inches. Thank you for verifying the calculation.