heat lost by metal is gained by water
water mass * specific heat * temp change = metal mass * specific heat * temp change
A calorimeter is filled with 250.0 g of water at 24.6oC. A 60.0 g sample of a metal at 100.0 oC is dropped in this calorimeter and causes the temperature to increase a total of 4.5oC. What is the specific heat of the metal (in J/g°C)? Ignore the calorimeter in this problem
1 answer
1 answer