Let the calf be tried at the corner A of the square lawn.Then, the increase in area = difference of two sectors of central angle 90 each and radii 11.5m (6m+5.5m) and 6m, which is shaded region in figure so,required increase in area = [90/360into pia into( 11.5)into 11.5-90/360into pia into6into ]msq
=75.625m.sq
A calf is tied with a rope of length 6m at the corner of a square grassy lawn of side 20m. If the length of the rope is increased by 5.5m, find the increase in area of grassy lawn in whi the calf can graze.
4 answers
Did you make a sketch?
The area reached by the horse is 1/4 of a circle with original radius of 6 m
that area = (1/4)π(36) = 9π m^2
after lengthening of rope, r = 11.5 m
new area for grazing = (1/4)π(11.5)^2 m^2
= 33.0625π m^2
So what is the increase in area ?
The area reached by the horse is 1/4 of a circle with original radius of 6 m
that area = (1/4)π(36) = 9π m^2
after lengthening of rope, r = 11.5 m
new area for grazing = (1/4)π(11.5)^2 m^2
= 33.0625π m^2
So what is the increase in area ?
Thanx
No idea
1 answer