A calculator manufacturing company checks 500 calculator units, and 25 of them have non-functioning keys. Approximate the relative frequency of a non-defective unit from this batch of items. Express your answer in the simplest form of a fraction.(1 point)
Responses
25500
Start Fraction 25 over 500 End Fraction
475500
Start Fraction 475 over 500 End Fraction
1920
Start Fraction 19 over 20 End Fraction
120
5 answers
Start Fraction 475 over 500 End Fraction = Start Fraction 19 over 20 End Fraction
its 19 over 20
Yes, that is correct. The relative frequency of a non-defective unit is 19/20.
x/(x+2)/((1/x)+1/(x+2))
A: x^2/2
B: x^2/x+2
C: x^2/2x+2
D: x^2+2x+2/2x+2
A: x^2/2
B: x^2/x+2
C: x^2/2x+2
D: x^2+2x+2/2x+2
We can simplify the expression as follows:
x / (x + 2) / ((1/x) + (1/(x + 2)))
= x / (x + 2) / ((x + (x + 2)) / (x(x + 2))) [Taking LCM and simplifying fractions]
= x * x(x + 2) / (x + 2) * (2x + 2) [Dividing by a fraction is equivalent to multiplying by its reciprocal]
= x^2 / (2x + 2)
= x^2 / 2(x + 1)
Therefore, the answer is (C) x^2/2x+2.
x / (x + 2) / ((1/x) + (1/(x + 2)))
= x / (x + 2) / ((x + (x + 2)) / (x(x + 2))) [Taking LCM and simplifying fractions]
= x * x(x + 2) / (x + 2) * (2x + 2) [Dividing by a fraction is equivalent to multiplying by its reciprocal]
= x^2 / (2x + 2)
= x^2 / 2(x + 1)
Therefore, the answer is (C) x^2/2x+2.
1 answer