A cable is 32 feet 10 1/2 inches long is to be cut into 8 1/2 inches lengths. Allow 1/16 inch for each saw cut.
5 answers
What is your question?
How do you account for the 1/16 inch cuts?
The saw is probably about 1/16-inch-thick -- therefore you'll have some waste.
Would you add the 1/16 inch to the 8 1/2 inch to account for each cut and then divide by the 32 FT 10 1/2 inch? or what? I'm confused on how to go about doing the problem.
What is the question you're trying to solve?