To find out which one has the greater momentum, we can use the momentum formula:
\[ \text{Momentum} (p) = \text{mass} (m) \times \text{velocity} (v) \]
First, we need to convert the speeds from kilometers per hour (km/h) to meters per second (m/s) for both the bee and Ferdinand.
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Converting bee's speed: \[ 42 \text{ km/h} \times \frac{1000 \text{ m}}{1 \text{ km}} \times \frac{1 \text{ h}}{3600 \text{ s}} = 11.67 \text{ m/s} \]
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Converting Ferdinand's speed: \[ 11 \text{ km/h} \times \frac{1000 \text{ m}}{1 \text{ km}} \times \frac{1 \text{ h}}{3600 \text{ s}} = 3.06 \text{ m/s} \]
Now we can calculate the momentum for each:
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Momentum of the bee:
- Mass of the bee = 0.1 g = 0.0001 kg
- Velocity of the bee = 11.67 m/s
\[ p_{\text{bee}} = m_{\text{bee}} \times v_{\text{bee}} = 0.0001 \text{ kg} \times 11.67 \text{ m/s} = 0.0001167 \text{ kg m/s} \]
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Momentum of Ferdinand:
- Mass of Ferdinand = 1000 kg
- Velocity of Ferdinand = 3.06 m/s
\[ p_{\text{Ferdinand}} = m_{\text{Ferdinand}} \times v_{\text{Ferdinand}} = 1000 \text{ kg} \times 3.06 \text{ m/s} = 3060 \text{ kg m/s} \]
Finally, we can compare the momentum values:
- Momentum of the bee: \(0.0001167 \text{ kg m/s}\)
- Momentum of Ferdinand: \(3060 \text{ kg m/s}\)
Clearly, Ferdinand has the greater momentum.