Question

a busy bee with a mass of 0.1 g zips around ferdinand's horns at a speed of 42 km/h. Ferdinands, who happens to be a bull, has a mass of 1000kg and runs at a speed of 11 km/h in an attempt to serve and make the bee dizzy. which one has the greater momentum.

Answer 1

To find out which one has the greater momentum, we can use the momentum formula:

\[
\text{Momentum} (p) = \text{mass} (m) \times \text{velocity} (v)
\]

First, we need to convert the speeds from kilometers per hour (km/h) to meters per second (m/s) for both the bee and Ferdinand.

1. **Converting bee's speed:**
\[
42 \text{ km/h} \times \frac{1000 \text{ m}}{1 \text{ km}} \times \frac{1 \text{ h}}{3600 \text{ s}} = 11.67 \text{ m/s}
\]

2. **Converting Ferdinand's speed:**
\[
11 \text{ km/h} \times \frac{1000 \text{ m}}{1 \text{ km}} \times \frac{1 \text{ h}}{3600 \text{ s}} = 3.06 \text{ m/s}
\]

Now we can calculate the momentum for each:

1. **Momentum of the bee:**
- Mass of the bee = 0.1 g = 0.0001 kg
- Velocity of the bee = 11.67 m/s

\[
p_{\text{bee}} = m_{\text{bee}} \times v_{\text{bee}} = 0.0001 \text{ kg} \times 11.67 \text{ m/s} = 0.0001167 \text{ kg m/s}
\]

2. **Momentum of Ferdinand:**
- Mass of Ferdinand = 1000 kg
- Velocity of Ferdinand = 3.06 m/s

\[
p_{\text{Ferdinand}} = m_{\text{Ferdinand}} \times v_{\text{Ferdinand}} = 1000 \text{ kg} \times 3.06 \text{ m/s} = 3060 \text{ kg m/s}
\]

Finally, we can compare the momentum values:

- Momentum of the bee: \(0.0001167 \text{ kg m/s}\)
- Momentum of Ferdinand: \(3060 \text{ kg m/s}\)

Clearly, Ferdinand has the greater momentum.