A business man buys x bread at the rate of 12 breads for 60.8 of bread were bad, so

Question

he sold the remaining at the rate of 4 bread for 24 and make a profit of twelve naira, how many bread did he buy

Answer 1

To find how many breads the businessman bought, let's break down the information step by step.

1. Let the total number of breads bought be \( x \).

2. The cost for 12 breads is 60.8, so the cost per bread is: \[ \text{Cost per bread} = \frac{60.8}{12} = 5.0667 \text{ (approximately)} \]

3. Thus, the total cost for \( x \) breads will be: \[ \text{Total cost} = x \cdot 5.0667 \]

4. It is stated that 80 of the breads were bad. Therefore, the number of good breads left is: \[ \text{Good breads} = x - 80 \]

5. The selling price for the remaining good breads is given as 4 breads for 24, so the selling price per bread is: \[ \text{Selling price per bread} = \frac{24}{4} = 6 \]

6. Therefore, the total selling price for the good breads will be: \[ \text{Total selling price} = (x - 80) \cdot 6 \]

7. The problem states that he made a profit of 12 naira, which gives us the equation: \[ \text{Total selling price} - \text{Total cost} = 12 \] Substituting in our expressions: \[ (x - 80) \cdot 6 - x \cdot 5.0667 = 12 \]

8. Expanding the equation: \[ 6x - 480 - 5.0667x = 12 \]

9. Combine like terms: \[ (6 - 5.0667)x - 480 = 12 \] \[ 0.9333x - 480 = 12 \]

10. Add 480 to both sides: \[ 0.9333x = 492 \]

11. Solve for \( x \): \[ x = \frac{492}{0.9333} \approx 528 \]

Thus, the businessman bought approximately 528 breads.