h = -1/2 g t^2 Vo t + Ho
g is gravitational acceleration ... 32 ft/s^2
Vo is initial velocity .. 4 ft/s
Ho is initial height ... 0
A bush cricket jumps from the ground into the air with an initial vertical velocity of 4 feet per second. Write an equation that gives the cricket’s height (in feet) as a function of the time (in seconds) since it left the ground. After how many seconds is the cricket 3 inches off the ground? Does the cricket jump higher than 3 inches?
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