A bush baby, an African primate, is capable of leaping vertically to the remarkable height of 2.3 m. To jump this high, the bush baby accelerates over a distance of 0.16 m while extending the legs. The acceleration during the jump is approximately constant. What is the acceleration in m/s squared?

3 answers

well, the energy the body delivers to the gravity is mgh. That has to equal force*distance= ma*distance

mgh=ma*distance
g*2.3=a*.16

solve for a.
140 m/s^2
Could you maybe just actually give the answer next time?
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