A buoy bobs up and down in the ocean. The waves have a wavelength of 2.5 meters, and they pass the buoy at a speed of 4.0 meters/second. What is the frequency of the waves?

Question

1.6 Hertz.
10 Hertz.
7.5 Hertz.
4 Hertz.

Answer 1

To find the frequency of the waves, we can use the formula:

\[ \text{Frequency} (f) = \frac{\text{Speed} (v)}{\text{Wavelength} (\lambda)} \]

Given:

• Speed (\(v\)) = 4.0 meters/second
• Wavelength (\(\lambda\)) = 2.5 meters

Substituting the values into the formula:

\[ f = \frac{4.0 , \text{m/s}}{2.5 , \text{m}} = 1.6 , \text{Hertz} \]

Thus, the frequency of the waves is 1.6 Hertz.

Answer 2

Are you sure?

Answer 3

Let's double-check the calculation step by step.

We have:

• Wave speed (\(v\)) = 4.0 m/s
• Wavelength (\(\lambda\)) = 2.5 m

Using the formula for frequency:

\[ f = \frac{v}{\lambda} \]

Let's substitute the values in:

\[ f = \frac{4.0 , \text{m/s}}{2.5 , \text{m}} \]

Calculating that gives:

\[ f = \frac{4.0}{2.5} = 1.6 , \text{Hertz} \]

So, I can confirm that the frequency is indeed 1.6 Hertz. Thank you for your patience!

Answer 4

You are at a pool party and notice that 2 waves pass by a floating ball in 4 seconds. If the distance between each wave crest is 2 meters, what is the speed of the waves?
1 m/s.
6 m/s.
2 m/s.
1.5 m/s.

Answer 5

To find the speed of the waves, we can use the formula:

\[ \text{Speed} (v) = \text{Frequency} (f) \times \text{Wavelength} (\lambda) \]

First, we need to determine the frequency of the waves.

Step 1: Calculate the frequency.

You observe that 2 waves pass by in 4 seconds, so the frequency \(f\) can be calculated as follows:

\[ f = \frac{\text{Number of waves}}{\text{Time (seconds)}} \]

\[ f = \frac{2 , \text{waves}}{4 , \text{seconds}} = 0.5 , \text{Hertz} \]

Step 2: Use the wavelength.

We are given that the distance between each wave crest (wavelength) is:

\[ \lambda = 2 , \text{meters} \]

Step 3: Calculate the speed.

Now we can calculate the speed of the waves:

\[ v = f \times \lambda \]

\[ v = 0.5 , \text{Hz} \times 2 , \text{m} = 1 , \text{m/s} \]

Thus, the speed of the waves is 1 m/s.

Answer 6

A student moves the end of a compressed coiled spring up and down to demonstrate wave motion. She then moves the compressed coiled spring faster but keeps everything else the same. Which characteristic will increase?

Answer 7

When the student moves the end of the compressed coiled spring faster while keeping everything else the same, the frequency of the wave will increase.

Explanation:

• Frequency is the number of waves that pass a point in a given amount of time. If the student moves the spring faster, more waves are created in the same period, resulting in a higher frequency.
• Wavelength will typically decrease as frequency increases (for a given wave speed), maintaining the wave speed constant.

Therefore, the characteristic that will increase is the frequency of the waves produced in the spring.