force*distance= 1/2 m v^2 (bullet)
force*.04m= 1/2 * .005kg * 600^2 m^2/s^2
solve for force.
a bullet with a mass of 5 g and a speed of 600 m/s penetrates a tree to a depth of 4 cm. Assume that a constant frictional force stops the bullet.
Calculate the magnitude of this frictional force.
I used KE = 1/2 mv^2 = 900 J
then F (friction ) = W/d = 22500 N
BUT I don't know if it's positive or negative. please help. I just don't get it. Thank you.
2 answers
So F = 22500
Am I right in thinking it is POSITIVE?
Am I right in thinking it is POSITIVE?