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A bullet whose mass is 1.0 x 10-3 kg leaves a 5.0 kg rifle with a muzzle velocity of 1.0 x 103 m/s. It strikes a stationary block of wood whose mass is 1.0 kg and remains embedded in it. The kinetic energy of the bullet as it travels towards the wooden block is?

2 answers

KE = 0.5M*V^2.

M = 1.*10^-3 kg.
V = 1.*10^3 m/s.
Solve for KE.
Acheetan 101m along 41m acceleration 9•5
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