A bullet of mass 3.0g moving at 500m/s hits a tree and pierced 20cm into the trunk of the tree.what is the resistimg force offered by the tree?

Answer 1

Force * distance = Work done by bullet = Initial kinetic energy of the bullet

Solve for the force

F = M*V^2/(2*X)
= 3*10^-3*(500)^2/(2*0.2) Newtons
= 1875 N