0=m1•v1- m2•v2
v2 = m1•v1/ m2 =0.02•150/2 =1.5 m/s
a bullet of mass 20 gram is horizontly fired with a velocity 150 mtr/sec from a pistol of mass 2 kg. what is the recoil velocity of the pistol?
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no answre
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Mass of bullet ( m1 ) = 0.02 kg ( after changing into gram to kilogram )
=> initial velocity ( u1 ) = 0 m/s
=> final velocity ( v1 ) = 150 m/s
Mass of pistol ( m2 ) = 2kg
=> initial velocity ( u2 ) = 0 m/s
=> final velocity ( v2 ) = ?
Let the final velocity of pistol be v
so,
BY THE LAW OF CONSERVATION OF MOMENTUM
=> m1u1 + m2u2 = m1v1 + m2v2
=> 0.02 × 0 + 2 × 0 = 0.02 × 150 + 2 × v
0 + 0 = 3 + 2v
3 = 2v
v = 3/2
v = 1.5 m/s
hope this will help you
Mass of bullet ( m1 ) = 0.02 kg ( after changing into gram to kilogram )
=> initial velocity ( u1 ) = 0 m/s
=> final velocity ( v1 ) = 150 m/s
Mass of pistol ( m2 ) = 2kg
=> initial velocity ( u2 ) = 0 m/s
=> final velocity ( v2 ) = ?
Let the final velocity of pistol be v
so,
BY THE LAW OF CONSERVATION OF MOMENTUM
=> m1u1 + m2u2 = m1v1 + m2v2
=> 0.02 × 0 + 2 × 0 = 0.02 × 150 + 2 × v
0 + 0 = 3 + 2v
3 = 2v
v = 3/2
v = 1.5 m/s
hope this will help you
Yes this question is right that's why I solve this question... 👍👍
2 answers