a bullet of mass 0.03kg enters a block of wood with a velocity 600m/s & penatrate to a depth of 0.2m .Calculate the average force of the wood to the penetration of the bullet
4 answers
60000
27000
change of momentum = .03*600 = 18
average speed = 300
time = .2/300
Force = change of momentum/change of time
= 18 *300/.2 Newtons
= 90*300
=27,000 agree
average speed = 300
time = .2/300
Force = change of momentum/change of time
= 18 *300/.2 Newtons
= 90*300
=27,000 agree
Thanks sir