A bullet leaves a rifle with a muzzle velocity of 521 m/s .while accelerating through the barrel of the rifle , the bullet moves a distance of 0.840m.determine the acceleration if the bullet. (Assume a uniform acceletlration).

Answer 1

Vf^2=vi^2+2*acceleration*distance
solve for acceleration

Answer 2

I have 2 answers
1. u=521m/s
v=0
s= 0.840
now we use v^2=u^2+2as
0^2=521^2+2xax0.840
0=2771441+1.68a
1.68a=2771441
a= 2771441 by 1.68
a=161572.02
that's the first answer

2.velocity= distance by time
velocity = 521ms
distance = 0.840m
therefore time =0.840 by 521
=0.0016s
a=velocity by time
=521 by 0.0016 = 325625ms^2
that's my second answer
please help

Answer 3

this is not correct answer

Answer 4

I have been asked another question.

Answer 5

SORRY THIS IS RIGHT ANSWER.

Answer 6

THANKS FOR GIVING THIS ANSWER.