A bullet is fired from a rifle 3m above the ground level at a target 200m away. The initial velocity of the bullet is 300 m/s. How low must the center of the target be off the ground for the bullet to successfully hit it?

Answer 1

t=s/v = 200/300 = 0.67 s.

Δy=gt²/2=9.8•0.67²/2 =2.18 m
h=H-Δy=3-2.18= 0.82 m