momentum is conserved
10 * 1.5 = (90 + 10) * v
A bullet having a mass of 10g and moving with a speed of 1.5m/s penetrates a thick wooden plank of mass 90g. The plank was initially at rest. The bullet gets embedded in the plank and both moves together. Determine their velocity
9 answers
O.15m/s
0.15m/s
Jsjdh
0.15
I want the answer step wise...
0.15m/s
0.15m/s
Ans. Data: m, 10 g=10 x 10-3 kg, u, -1.5 m/s, m2=90 g = 90 × 10-3 kg. u, 0 m/s, v₁ = v₂ =v=?
=
By the law of conservation of momentum,
m,u,+m,u,m,v,+m₂v₂
As u₁ = 0 m/s and v₁ = v₁ =v, we have
m,u,(m, +m₂) v
..U = mu, m+m₂
10 x 10 kg x 1.5 m/s 10 x 10 kg +90 x 10 kg
110 x 1.5 100 m/s = 0.15 m/s
The speed with which the plank containing the bullet moves = 0.15 m/s
=
By the law of conservation of momentum,
m,u,+m,u,m,v,+m₂v₂
As u₁ = 0 m/s and v₁ = v₁ =v, we have
m,u,(m, +m₂) v
..U = mu, m+m₂
10 x 10 kg x 1.5 m/s 10 x 10 kg +90 x 10 kg
110 x 1.5 100 m/s = 0.15 m/s
The speed with which the plank containing the bullet moves = 0.15 m/s
3 answers