Initial momentum
= 2(200) -9(20) = 400 - 180 = 220
final momentum = 11 v
Conservation of momentum, Newton's First Law --->
220 = 11 v
so
v = 20 m/s
A bullet A of mass 2kg travelling at 200m/s emblezes itself in a wooden block of mass 9kg moving in the opposite direction. At 20m/s. Calculate the velocity of the block when the bullet comes to rest inside the block. And what principle is used in the direction
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