the equation is
y = -4.9/(29 cos63°)^2 x^2 + tan63° x + 0.9
so see where y=34.5 (if ever)
A building’s 10th floor (34.5 m high) is blazing with fire. A fire truck arrived at the scene and the fire
men shoots water from their hose. The water leaves the hose at the speed of 29 m/s, at an angle of
63° and is held at 0.90 m from the ground. Will the water reach the fire? If so, how far from the
building should the hose be so the fire could be put out?
1 answer