Halflife for Sr-90
T =28.79 yr
Decay constant
λ=ln2/T =0.693/28.79•365•24•3600 =
=7.63•10^-10 s^-1
Initial number of nuclei
Nₒ=m/mₒ=4.8/89.9077•1.66•10^-27 = =3.2•10^25.
Initial activity
Aₒ = λ •Nₒ =7.63•10^-10 • 3.2•10^25= =2.44•10^16 Bq.
A =10 counts/min =
=10/60 counts/s =0.167 Bq.
From the law of radioactive decay N=Nₒ•e^- λ•t
A=Aₒ•e^- λ•t,
A/Aₒ= e^ -λ•t,
A/Aₒ=0.167/2.44•10^16=6.84•10^-18
t = - ln(A/Aₒ)/λ = 39.5/7.63•10^-10 =
=5.18•10^10 s =1643 years.
A building has become accidentally contaminated with radioactivity. The longest-lived material in the building is strontium-90. (The atomic mass of Sr is 89.9077 u.) If the building initially contained 4.8 kg of this substance and the safe level is less than 10.0 counts/min, how long will the building be unsafe? (in years)
1 answer
1 answer