Ask a New Question

A building, B, is observed from two points P and Q which are 250 m apart. The angles PQB and QPB are found to be 67 degrees and 73 degrees respectively. What is the distance, to the nearest metre, of P from the building?

1 answer

angle B is 180-67-73 = 40°
Now, using the law of sines

250/sin40° = PB/sin67°

Ask a New Question or answer this question.

Similar Questions

From a point 35 m from a building and 2 m above the ground , the angle of elevation of the top of the building is observed to be
1. 2 answers
from a point 35 meter from a building and 2 meter above the ground, the angle of the elevation of the top of the building is
1. 2 answers
From a point 36 meters from a building and 2.3 meters above the ground, the angle of elevation of the top of the building is
1. 1 answer
6 of 156 of 15 Items Question Which of the following is true about Divine Proportion? Select all that apply. (2 points)
1. 1 answer

more similar questions