Bug dv/dt = ab = 60 mi/h/2.4s = 25 mi/(s h)
= 40.2 km /(3600 s^2)
Sal dv/dt = as = 60/2.8 = 21.4 mi/(s h)
=34.4 km/3600s^2
v = 75 km/h = 75 km/3600s
then v = a t or t = v/a
Bug:
t = 75 km/3600 s / 40.2 km/3600s^2
= 1.87 seconds
d = (1/2) a t^2 =
OR
use half max (average) speed
Vaverage = 75/(2*3600 )km/s
d = 1.87 * 75/(2*3600) = .0195 km
= 19.5 meters
do the same for the other car
A Bugatti Veyron 16.4 can accelerate from 0 to 60 mi/h in 2.4 s. The Saleen S7 Twin Turbo goes "from 0 to 60" in 2.8 s. Determine the distance that the Bugatti Veyron would travel in the time it takes to reach 75 km/h, the speed limit on many Canadian roads. Compare your answer to the distance that the Saleen S7 Twin Turbo would travel while accelerating to the same final speed.
1 answer