A bucket of water has a weight of 40N.a man lifts the bucket by applying an upward force of 20N.at the same time a child pulls the bucket along the ground with a horizontal force of 10N...calculate the resultant force on the bucket

Answer 1

X = 10 N.
Y = 20 N.

tan A = Y/X = 20/10 = 2.0
A = 63.43o

R=Y/sin A = 20/sin63.43 = 22.4N[63.43o]


a

Answer 2

I want to draw a lebelled force diagram to indicate how the forces exerted on the backet