A bucket contains the following vegetables 1 squash, 2 carrots, 4 heads of broccoli, 2 artichoke and 5 green beans. Ronnie picks a vegetable at random and does not replace it. Sidney pick a vegetable at random what is the probability that Ronnie gets a carrot and Sydney gets a green bean? Please help someone!!

Answer 1

There are a total of 1+2+4+2+5=14 vegetables in the bucket.

The probability that Ronnie picks a carrot on the first pick is 2/14 or 1/7. Since Ronnie does not replace the vegetable, there are now only 13 vegetables left in the bucket.

The probability that Sydney picks a green bean on the second pick is 5/13.

To find the probability of both events happening in sequence, we need to multiply their individual probabilities:

(1/7) x (5/13) = 5/91

Therefore, the probability that Ronnie picks a carrot and Sydney picks a green bean is 5/91.