A bucket contains the following vegetables. 1 squash 2 carrots 4 heads of broccoli 2 artichokes and 5 green beans Ronnie picks a vegetable at random snd does not replace it. Then Sydney picks a vegetable at random Whst is the probability that Ronnie gets a carrot and Sydney gets a green bean? Help!!!

3 answers

There are a total of 14 vegetables in the bucket.

The probability that Ronnie picks a carrot is 2/14 or 1/7.

After Ronnie picks a vegetable, there are now 13 vegetables in the bucket. The probability that Sydney picks a green bean is 5/13 (since there are still 5 green beans left, but there are now 13 vegetables in total).

To find the probability of both events happening (Ronnie getting a carrot and Sydney getting a green bean), we multiply the probabilities:

(1/7) * (5/13) = 5/91

Therefore, the probability that Ronnie gets a carrot and Sydney gets a green bean is 5/91.
The probability of a basketball player making a basket is 1/5. How many baskets would you expect her to make after 40 shots?
The expected number of baskets is equal to the probability of making a basket multiplied by the number of shots taken.

Expected number of baskets = probability of making a basket x number of shots taken

In this case, the probability of making a basket is 1/5, and the number of shots taken is 40.

Expected number of baskets = (1/5) x 40 = 8

Therefore, we would expect the basketball player to make 8 baskets after 40 shots.
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