A brick weight 17.8N and is resting on the ground. Its dimensions are 0.203mx0.089mx0.0570m. A number of the bricks are then stacked on top of this one.

Question

What is the smallest number of whole bricks (including the one on the ground) that could be used, so that their weight creates a pressure of a least one atmosphere on the ground beneath the first brick? Take P =1.013x105N/m2

Answer 1

P=F/A=NW/A
N=PA/W =
=1.013•10⁵•0.203•0.089/17.8=102.8 ≈103