A brick is thrown upward from the top of a building at an angle of 35° to the horizontal and with an initial speed of 14 m/s. If the brick is in flight for 3s, how tall is the building?
2 answers
I told you how to do this type of problem earlier.
Vo = 14m/s[35o].
Yo = 14*sin35 = 8.03 m/s.
Y = Yo + g*Tr = 0 at max ht.
8.03 - 9.8Tr = 0,
Tr = 0.82 s. = Rise time.
Tf = Tr = 0.82 s. = Time to fall back to top of bldg.
T = 3-(0.82+0.82) = 1.36 s. = Time to fall from top of bldg. to gnd.
h = Vo*T + 0.5g*T^2.
Vo = 14 m/s, T = 1.36 s, g = + 9.8 m/s^2, h = ?.
Yo = 14*sin35 = 8.03 m/s.
Y = Yo + g*Tr = 0 at max ht.
8.03 - 9.8Tr = 0,
Tr = 0.82 s. = Rise time.
Tf = Tr = 0.82 s. = Time to fall back to top of bldg.
T = 3-(0.82+0.82) = 1.36 s. = Time to fall from top of bldg. to gnd.
h = Vo*T + 0.5g*T^2.
Vo = 14 m/s, T = 1.36 s, g = + 9.8 m/s^2, h = ?.
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