A breeder of guinea pigs has 1 male and 2 females in a red cage, and two males and one female in a blue cage. A visiting child picks up a guinea pig from the red cage with his right hand and a guinea pig from the blue cage with his left hand and then puts each guinea pig into the wrong cage. What is the probability that each cage will now have 3 animals of the same sex?

asked by Hero

4 years ago

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1 answer

red: P(male) = 1/3
blue: P(female) = 1/3
so, 1/9 that he will get both the needed gp's.

answered by oobleck

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Question

A breeder of guinea pigs has 1 male and 2 females in a red cage, and two males and one female in a blue cage. A visiting child picks up a guinea pig from the red cage with his right hand and a guinea pig from the blue cage with his left hand and then puts each guinea pig into the wrong cage. What is the probability that each cage will now have 3 animals of the same sex?

1 answer

red: P(male) = 1/3
blue: P(female) = 1/3
so, 1/9 that he will get both the needed gp's.

Ask a New Question or answer this question.

oobleck · Answer

red: P(male) = 1/3 blue: P(female) = 1/3 so, 1/9 that he will get both the needed gp's.