A Brass rod 50.0 cm long expands 0.0734 cm when heated. Find the temperature change.

1 answer

Linear Temperature Expansion Coefficient
α =ΔL/(L•ΔT),
for Brass α = 18.7•10^-6 K^-1,
ΔT = ΔL/(L• α) =
= 0.000734/(0.5•18.7•10^-6)=
= 78.5 K