diameter increases in proportion to alpha and delta T. You want the brass diameter to expand 0.01 cm more than the aluminum
(T-20)[10.00*alphab - 10.01*alphaa] = 0.01
Look up the alpha values and solve for T
It can be done if a melting point is not exceeded.
a brass ring of diameter 10.00cm at 20.0 degrees Celsius is heated and slipped over an aluminum rod of diameter 10.01cm at 20.0 degrees Celsius. Assuming the average coefficients of linear expansion are constant, (a) to what temperature must this combination be cooled to separate them? is this attainable?
(b) What if? What if the aluminum rod were 10.02cm in diameter?
thanks.
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