You need to find the vertical velocity of the ball at launch.
The PE at the top=KE at launch
mg*22=1/2 m v^2
v= sqrt (2*g*22) m/s
now, considering just the period throwing
vf^2=vi^2+2ad
vf=above
vi=0
d=1.45m
solve for a
A boy's hand pushes a ball through a vertical distance of 1.45 m as he throws the ball straight upward. Once the ball leaves his hand it travels an additional 22 m (straight up) before returning to earth. Find the acceleration of the ball while it was in the boy's hand
1 answer