A boy throws a ball with an initial speed of 40.0 m/s. The angle of the thrown ball is 33.0° above the horizontal.(Neglect the height of the boy and air resistance.)

Question

(a) What is the ball's speed in the horizontal direction just before it hits the ground?
(b) How long is the ball in the air?

Answer 1

The horizontal motion is with uniform speed vx=v0•cos33=40•0.84=33.55m/s
t=(2v0sinα)/g=2•40•0.54/9.8=4.45 s