A boy sledding down a hill accelerates at 1.20 m/s2. If he started from rest, in what distance would he reach a speed of 7.00 m/s?

Answer 1

Use:
v(t) = v(0) + a t
With values:
(7.00m/s) = (0.00m/s) + (1.20m/s^2) t
Solve for t.

Answer 2

V^2 = Vo^2 + 2a*d
d = (V^2-Vo^2)/2a
d = (7^2-0)/2.4