a boy runs 100m along the east,then he turns to his left side at right angle and runs for 50m along the north direction.find the distance and the magnitude of the displacement .

Answer 1

Let
x-axis => due east
y-axis => due north
then
100m due east and 50m due north
=>
New position P(100,50)
distance by Pythagoras, D=sqrt(100^2+50^2)
angle (from x-axis)= tan^-1(y/x)=tan^-1(50/100)=tan^-1(1/2) [ in the first quadrant]