A boy left his house to jog he walk 300 steps west in a time of 5 minutes; he quickly turned around and walked 180 steps east in a time 2 minutes. If one step is equivalent to 0.60m, calculate (a) the total distance he did walked, (b) his average speed in m/s, (C) his displacement (d) his average velocity in m/s

1 answer

(a) To calculate the total distance he walked, we need to add the distances he walked going west and east.

Distance west = 300 steps * 0.60m/step = 180m
Distance east = 180 steps * 0.60m/step = 108m

Total distance = Distance west + Distance east
Total distance = 180m + 108m = 288m

Therefore, the total distance he walked is 288 meters.

(b) To calculate his average speed, we use the formula:

Average speed = Total distance / Total time

Total time = 5 minutes + 2 minutes = 7 minutes

Converting this to seconds: 7 minutes * 60 seconds/minute = 420 seconds

Average speed = 288m / 420s

Therefore, his average speed is approximately 0.686 m/s.

(c) To calculate his displacement, we need to find the difference between the total distance he walked west and the total distance he walked east.

Displacement = Distance west - Distance east
Displacement = 180m - 108m

Therefore, his displacement is 72m to the west.

(d) To calculate his average velocity, we use the formula:

Average velocity = Displacement / Total time

Average velocity = 72m / 420s

Therefore, his average velocity is approximately 0.171 m/s to the west.